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x^2=12.5
We move all terms to the left:
x^2-(12.5)=0
We add all the numbers together, and all the variables
x^2-12.5=0
a = 1; b = 0; c = -12.5;
Δ = b2-4ac
Δ = 02-4·1·(-12.5)
Δ = 50
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{50}=\sqrt{25*2}=\sqrt{25}*\sqrt{2}=5\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-5\sqrt{2}}{2*1}=\frac{0-5\sqrt{2}}{2} =-\frac{5\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+5\sqrt{2}}{2*1}=\frac{0+5\sqrt{2}}{2} =\frac{5\sqrt{2}}{2} $
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